Optimal. Leaf size=296 \[ \frac{7 b^{9/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right ),\frac{1}{2}\right )}{15 c^{11/4} \sqrt{b x^2+c x^4}}+\frac{14 b^2 x^{3/2} \left (b+c x^2\right )}{15 c^{5/2} \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{b x^2+c x^4}}-\frac{14 b^{9/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{15 c^{11/4} \sqrt{b x^2+c x^4}}-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c} \]
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Rubi [A] time = 0.297892, antiderivative size = 296, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.286, Rules used = {2024, 2032, 329, 305, 220, 1196} \[ \frac{14 b^2 x^{3/2} \left (b+c x^2\right )}{15 c^{5/2} \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{b x^2+c x^4}}+\frac{7 b^{9/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{15 c^{11/4} \sqrt{b x^2+c x^4}}-\frac{14 b^{9/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{15 c^{11/4} \sqrt{b x^2+c x^4}}-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c} \]
Antiderivative was successfully verified.
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Rule 2024
Rule 2032
Rule 329
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{x^{11/2}}{\sqrt{b x^2+c x^4}} \, dx &=\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c}-\frac{(7 b) \int \frac{x^{7/2}}{\sqrt{b x^2+c x^4}} \, dx}{9 c}\\ &=-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c}+\frac{\left (7 b^2\right ) \int \frac{x^{3/2}}{\sqrt{b x^2+c x^4}} \, dx}{15 c^2}\\ &=-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c}+\frac{\left (7 b^2 x \sqrt{b+c x^2}\right ) \int \frac{\sqrt{x}}{\sqrt{b+c x^2}} \, dx}{15 c^2 \sqrt{b x^2+c x^4}}\\ &=-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c}+\frac{\left (14 b^2 x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{15 c^2 \sqrt{b x^2+c x^4}}\\ &=-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c}+\frac{\left (14 b^{5/2} x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{15 c^{5/2} \sqrt{b x^2+c x^4}}-\frac{\left (14 b^{5/2} x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{b}}}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{15 c^{5/2} \sqrt{b x^2+c x^4}}\\ &=\frac{14 b^2 x^{3/2} \left (b+c x^2\right )}{15 c^{5/2} \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{b x^2+c x^4}}-\frac{14 b \sqrt{x} \sqrt{b x^2+c x^4}}{45 c^2}+\frac{2 x^{5/2} \sqrt{b x^2+c x^4}}{9 c}-\frac{14 b^{9/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{15 c^{11/4} \sqrt{b x^2+c x^4}}+\frac{7 b^{9/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{15 c^{11/4} \sqrt{b x^2+c x^4}}\\ \end{align*}
Mathematica [C] time = 0.0343946, size = 86, normalized size = 0.29 \[ \frac{2 x^{5/2} \left (7 b^2 \sqrt{\frac{c x^2}{b}+1} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{7}{4};-\frac{c x^2}{b}\right )-7 b^2-2 b c x^2+5 c^2 x^4\right )}{45 c^2 \sqrt{x^2 \left (b+c x^2\right )}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.19, size = 217, normalized size = 0.7 \begin{align*}{\frac{1}{45\,{c}^{3}}\sqrt{x} \left ( 10\,{c}^{3}{x}^{6}+42\,{b}^{3}\sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{-{\frac{cx}{\sqrt{-bc}}}}{\it EllipticE} \left ( \sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}},1/2\,\sqrt{2} \right ) -21\,{b}^{3}\sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{-{\frac{cx}{\sqrt{-bc}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}},1/2\,\sqrt{2} \right ) -4\,b{c}^{2}{x}^{4}-14\,{b}^{2}c{x}^{2} \right ){\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{\frac{11}{2}}}{\sqrt{c x^{4} + b x^{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{c x^{4} + b x^{2}} x^{\frac{7}{2}}}{c x^{2} + b}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{\frac{11}{2}}}{\sqrt{c x^{4} + b x^{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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